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Timing(again(again))


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#16 copemech

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Posted 25 April 2007 - 11:50 PM

ScottT, If you will please notice that the factory "tic" mark(noted as 4) has rotated approx 4mm counterclockwise from the(STD) position alignment with the right edge of the casting boss.

To plot the exact amount of piston travel vs crankshaft rotation you would need to plot on a parabolic curve. At exactly top or bottom center, there is NO movement of the piston in relation to the crankshaft. Piston travel is maximum in relation to degrees of rotation at 90 and 270 degrees from TDC and declines in either direction from that point. (almost)
:thumbup:

Edited by copemech, 26 April 2007 - 04:23 AM.

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#17 scudo

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Posted 26 April 2007 - 02:47 AM

Agree with Scott T. To retard the ignition loosen the bolts and rotate the backplate counter clockwise.


Page 12 of 16. sherco ignition guide.

Edited by scudo, 26 April 2007 - 03:02 AM.


#18 copemech

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Posted 26 April 2007 - 04:22 AM

At this point, I no longer care which way you rotate! :thumbup:
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#19 IKB

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Posted 26 April 2007 - 08:10 AM

I've got it! How about a lever on the bars with a cable that goes to the stator which can advance or retard the timing as desired :thumbup:

But I do think its been done before (1922!)!

#20 ScottT

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Posted 26 April 2007 - 02:18 PM

View Postcopemech, on Apr 26 2007, 12:50 AM, said:

ScottT, If you will please notice that the factory "tic" mark(noted as 4) has rotated approx 4mm counterclockwise from the(STD) position alignment with the right edge of the casting boss.

Ok thanks, its just your diagram was just a little bit confusing as to which way you had turned it, perhaps arrows might have been better.



View Postcopemech, on Apr 26 2007, 12:50 AM, said:

To plot the exact amount of piston travel vs crankshaft rotation you would need to plot on a parabolic curve.

No, the piston moves 60mm that is its stroke, as it moves fully up and down for every revolution of the crank. 1 revolution equals 120mm of piston movement 60mm up 60mm down, thats how 2 strokes work, so if its moving 120mm for 360deg of revolution then every 3deg of revolution the piston must move 1mm

#21 Marlintec

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Posted 26 April 2007 - 03:25 PM

View PostScottT, on Apr 26 2007, 03:18 PM, said:

...so if its moving 120mm for 360deg of revolution then every 3deg of revolution the piston must move 1mm

Certainly not.

Here you have the exact relationship and an approximate equation very useful for trials.

http://www.terra.es/personal9/marlintec/ta...ientopiston.pdf

Cheers,

JM.

P.D. Great job, Cope!

#22 ScottT

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Posted 26 April 2007 - 04:58 PM

Sorry I cant understand what that site is saying but now i see it i realise it isnt as straight forward as i thought.

#23 copemech

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Posted 26 April 2007 - 06:23 PM

Unfortunately, the simple theory of height vs rotation does not work, mostly because the piston accellerates and decellerates twice per revolution at a given crankshaft speed.

Here is a short study to relate this, makes my brane hurt!

piston speed


Gee, I should not have slammed this up in a hurry, as Marlintec already had a better timing diagram and formula, you do not have to read Spanish, just math! Spanish is easier!

Edited by copemech, 27 April 2007 - 01:52 AM.

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#24 Brian R

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Posted 27 April 2007 - 07:47 PM

;)





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