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Suppose there is an array with some numbers. We have to tell minimum how many numbers will be added with it to make the sum of the elements even. The number must be greater than 0. So if the sum of the elements is odd, we will add 1, but if the sum is already even, then we will add 2 with it to make it even.

begin s := 0 for each element e from arr, do s := e + s done if s is even, then return 2, otherwise 1 end

#include<iostream> using namespace std; int addMinNumber(int arr[], int n) { int sum = 0; for(int i = 0; i<n; i++) { sum += arr[i]; } return (sum % 2)? 1 : 2; } main() { int arr[] = {5, 8, 4, 7, 5}; int n = sizeof(arr)/sizeof(arr[0]); cout << "Minimum " << addMinNumber(arr, n) << " should be added"; }

Minimum 1 should be added

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